源代码：

1 package main  2   3 import (  4     "fmt"  5 )  6   7 type M_Rcd map[string]string  8   9 type T_Tbl struct { 10     tblname string 11     record  M_Rcd 12 } 13  14 type T_Kvdb struct { 15     dbname string 16     tbl    []T_Tbl 17 } 18  19 func (this *T_Kvdb) createDB(db T_Kvdb) { 20     this.dbname = db.dbname 21     this.tbl = make([]T_Tbl, 5) 22     fmt.Printf("\ncreate db \"%s\" success.\n", this.dbname) 23 } 24  25 func (this *T_Kvdb) newTbl(tblname string) T_Tbl { 26     var tbl T_Tbl 27     var length int 28     tbl.tblname = tblname 29     tbl.record = make(M_Rcd) 30  31     this.tbl = append(this.tbl, tbl) 32     length = len(this.tbl) 33     fmt.Printf("add new table \"%s\" to db \"%s\" success.\n", tblname, this.dbname) 34     return this.tbl[length-1] 35 } 36  37 /* 38  * 思路：循环检索数据库是否有该表，如果有该表，则进一步检索是否有该Key，如有则输出 39  */ 40 func (this *T_Kvdb) read(key string, tbl T_Tbl) { 41     for i, _ := range this.tbl { 42         if this.tbl[i].tblname == tbl.tblname { 43             for k, v := range this.tbl[i].record { 44                 if key == k { 45                     fmt.Printf("find result : {%s}\n", v) 46                     return 47                 } 48             } 49         } 50     } 51     fmt.Printf("have no table: \"%s\"\n", tbl.tblname) 52 } 53  54 /* 55  * 对表进行写数据 56  * 参数： 57  *        key:   键值 58  *        value: 键值对应的数据 59  *        tbl:   需要写如数据的表 60  */ 61 func (this *T_Kvdb) write(key string, value string, tbl T_Tbl) { 62     fmt.Printf("add {%s, %s} to table \"%s\"", key, value, tbl.tblname) 63     for i, _ := range this.tbl { 64         if this.tbl[i].tblname == tbl.tblname { 65             this.tbl[i].record[key] = value /* 对Table写入数据 */ 66             fmt.Println(" success.") 67             return 68         } 69     } 70  71     fmt.Println("have no table: ", tbl.tblname) 72 } 73  74 /* 75  * 删除表中key对应的{key, value} 76  */ 77 func (this *T_Kvdb) delete(key string, tbl T_Tbl) { 78  79     for i, _ := range this.tbl { 80         if this.tbl[i].tblname == tbl.tblname { 81             for k, _ := range this.tbl[i].record { 82                 if key == k { 83                     delete(this.tbl[i].record, key) // 删除key对应的数据{key, value} 84                     fmt.Printf("delete key success.\n") 85                     this.show() 86                     return 87                 } 88             } 89         } 90     } 91  92     fmt.Printf("have no table: %s\n", tbl.tblname) 93 } 94  95 /* 96  * 显示DB里所有Table的数据：{key, value} 97  */ 98 func (this *T_Kvdb) show() { 99     fmt.Print("show [")100     for i, _ := range this.tbl {101         for key, value := range this.tbl[i].record {102             fmt.Print("{
     ", key, ", ", value, "}")103         }104     }105 106     fmt.Print("]\n")107 }108 109 /*110  * 销毁表的思路：111  *      如有表数组[5]={表0，表1，表2，表3，表4}，现在需要删除{表2}，则可以利用append函数重新组合表数组112  *      来达到删除{表2}. 重组表数组的语句为：append(表头到表2（此处是开区间），（此处是闭区间）表3到表尾)113  */114 func (this *T_Kvdb) destroy(tbl T_Tbl) {115     for i, _ := range this.tbl {116         if this.tbl[i].tblname == tbl.tblname {117             this.tbl = append(this.tbl[:i], this.tbl[i+1:]...)118             fmt.Printf("destroy table success.\n")119             return120         }121     }122     fmt.Printf("have no table: \n", tbl.tblname)123 }124 125 func main() {126     var db T_Kvdb127     var tbl T_Tbl128 129     db.dbname = "student_management_system"130     db.createDB(db)131     tbl = db.newTbl("student")132     db.write("hezhixiong", "shanghai", tbl)133     db.write("zhangsan", "beijing", tbl)134     db.show()135     db.read("hezhixiong", tbl)136     db.delete("hezhixiong", tbl)137     fmt.Printf("db size = %d\n", len(db.tbl))138     db.destroy(tbl)139     fmt.Printf("db size = %d\n", len(db.tbl))140 }

程序输出：

1 create db "student_management_system" success. 2 add new table "student" to db "student_management_system" success. 3 add {hezhixiong, shanghai} to table "student" success. 4 show [{hezhixiong, shanghai}] 5 find result : {shanghai} 6 delete key success. 7 show [] 8 db size = 6 9 destroy table success.10 db size = 5